3(x+1)+(4x+1)=4(x+1)+3x

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Solution for 3(x+1)+(4x+1)=4(x+1)+3x equation:


Simplifying
3(x + 1) + (4x + 1) = 4(x + 1) + 3x

Reorder the terms:
3(1 + x) + (4x + 1) = 4(x + 1) + 3x
(1 * 3 + x * 3) + (4x + 1) = 4(x + 1) + 3x
(3 + 3x) + (4x + 1) = 4(x + 1) + 3x

Reorder the terms:
3 + 3x + (1 + 4x) = 4(x + 1) + 3x

Remove parenthesis around (1 + 4x)
3 + 3x + 1 + 4x = 4(x + 1) + 3x

Reorder the terms:
3 + 1 + 3x + 4x = 4(x + 1) + 3x

Combine like terms: 3 + 1 = 4
4 + 3x + 4x = 4(x + 1) + 3x

Combine like terms: 3x + 4x = 7x
4 + 7x = 4(x + 1) + 3x

Reorder the terms:
4 + 7x = 4(1 + x) + 3x
4 + 7x = (1 * 4 + x * 4) + 3x
4 + 7x = (4 + 4x) + 3x

Combine like terms: 4x + 3x = 7x
4 + 7x = 4 + 7x

Add '-4' to each side of the equation.
4 + -4 + 7x = 4 + -4 + 7x

Combine like terms: 4 + -4 = 0
0 + 7x = 4 + -4 + 7x
7x = 4 + -4 + 7x

Combine like terms: 4 + -4 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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