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3(x+1)+1+2x=-2(2x+2)+x
We move all terms to the left:
3(x+1)+1+2x-(-2(2x+2)+x)=0
We add all the numbers together, and all the variables
2x+3(x+1)-(-2(2x+2)+x)+1=0
We multiply parentheses
2x+3x-(-2(2x+2)+x)+3+1=0
We calculate terms in parentheses: -(-2(2x+2)+x), so:We add all the numbers together, and all the variables
-2(2x+2)+x
We add all the numbers together, and all the variables
x-2(2x+2)
We multiply parentheses
x-4x-4
We add all the numbers together, and all the variables
-3x-4
Back to the equation:
-(-3x-4)
5x-(-3x-4)+4=0
We get rid of parentheses
5x+3x+4+4=0
We add all the numbers together, and all the variables
8x+8=0
We move all terms containing x to the left, all other terms to the right
8x=-8
x=-8/8
x=-1
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