3(x+1)+1+2x=2(2x+2)+x,x

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Solution for 3(x+1)+1+2x=2(2x+2)+x,x equation: 



3(x+1)+1+2x=2(2x+2)+x.x

We move all terms to the left:

3(x+1)+1+2x-(2(2x+2)+x.x)=0

We add all the numbers together, and all the variables

2x+3(x+1)-(2(2x+2)+x.x)+1=0

We multiply parentheses

2x+3x-(2(2x+2)+x.x)+3+1=0



We calculate terms in parentheses: -(2(2x+2)+x.x), so:

2(2x+2)+x.x

We multiply parentheses

4x+x.x+4

Back to the equation:

-(4x+x.x+4)



We add all the numbers together, and all the variables

5x-(4x+x.x+4)+4=0

We get rid of parentheses

5x-4x-x.x-4+4=0

We add all the numbers together, and all the variables

x-x.x=0

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