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3(x+1)+1+2x=2(2x+2)+x.
We move all terms to the left:
3(x+1)+1+2x-(2(2x+2)+x.)=0
We add all the numbers together, and all the variables
2x+3(x+1)-(2(2x+2)+x.)+1=0
We multiply parentheses
2x+3x-(2(2x+2)+x.)+3+1=0
We calculate terms in parentheses: -(2(2x+2)+x.), so:We add all the numbers together, and all the variables
2(2x+2)+x.
We multiply parentheses
4x+x.+4
Back to the equation:
-(4x+x.+4)
5x-(4x+x.+4)+4=0
We get rid of parentheses
5x-4x-x.-4+4=0
We add all the numbers together, and all the variables
x-x.=0
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