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3(x+1)+11x=2(4+5x)-5
We move all terms to the left:
3(x+1)+11x-(2(4+5x)-5)=0
We add all the numbers together, and all the variables
3(x+1)+11x-(2(5x+4)-5)=0
We add all the numbers together, and all the variables
11x+3(x+1)-(2(5x+4)-5)=0
We multiply parentheses
11x+3x-(2(5x+4)-5)+3=0
We calculate terms in parentheses: -(2(5x+4)-5), so:We add all the numbers together, and all the variables
2(5x+4)-5
We multiply parentheses
10x+8-5
We add all the numbers together, and all the variables
10x+3
Back to the equation:
-(10x+3)
14x-(10x+3)+3=0
We get rid of parentheses
14x-10x-3+3=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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