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3(x+1)+1=5(x-2)
We move all terms to the left:
3(x+1)+1-(5(x-2))=0
We multiply parentheses
3x-(5(x-2))+3+1=0
We calculate terms in parentheses: -(5(x-2)), so:We add all the numbers together, and all the variables
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
3x-(5x-10)+4=0
We get rid of parentheses
3x-5x+10+4=0
We add all the numbers together, and all the variables
-2x+14=0
We move all terms containing x to the left, all other terms to the right
-2x=-14
x=-14/-2
x=+7
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