3(x+1)+2(2x-3)=5(x+1)+8

Solution for 3(x+1)+2(2x-3)=5(x+1)+8 equation:

3(x+1)+2(2x-3)=5(x+1)+8

We move all terms to the left:

3(x+1)+2(2x-3)-(5(x+1)+8)=0

We multiply parentheses

3x+4x-(5(x+1)+8)+3-6=0


We calculate terms in parentheses: -(5(x+1)+8), so:

5(x+1)+8

We multiply parentheses

5x+5+8

We add all the numbers together, and all the variables

5x+13

Back to the equation:

-(5x+13)


We add all the numbers together, and all the variables

7x-(5x+13)-3=0

We get rid of parentheses

7x-5x-13-3=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8