3(x+1)+2(2x-3)=5(x-1)=8

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Solution for 3(x+1)+2(2x-3)=5(x-1)=8 equation:



3(x+1)+2(2x-3)=5(x-1)=8
We move all terms to the left:
3(x+1)+2(2x-3)-(5(x-1))=0
We multiply parentheses
3x+4x-(5(x-1))+3-6=0
We calculate terms in parentheses: -(5(x-1)), so:
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
We add all the numbers together, and all the variables
7x-(5x-5)-3=0
We get rid of parentheses
7x-5x+5-3=0
We add all the numbers together, and all the variables
2x+2=0
We move all terms containing x to the left, all other terms to the right
2x=-2
x=-2/2
x=-1

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