3(x+1)+2(x+3)=8(x+2)-4

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Solution for 3(x+1)+2(x+3)=8(x+2)-4 equation: 



3(x+1)+2(x+3)=8(x+2)-4

We move all terms to the left:

3(x+1)+2(x+3)-(8(x+2)-4)=0

We multiply parentheses

3x+2x-(8(x+2)-4)+3+6=0



We calculate terms in parentheses: -(8(x+2)-4), so:

8(x+2)-4

We multiply parentheses

8x+16-4

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

5x-(8x+12)+9=0

We get rid of parentheses

5x-8x-12+9=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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