3(x+1)+2(x+4)=20

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Solution for 3(x+1)+2(x+4)=20 equation: 


Simplifying
3(x + 1) + 2(x + 4) = 20

Reorder the terms:
3(1 + x) + 2(x + 4) = 20
(1 * 3 + x * 3) + 2(x + 4) = 20
(3 + 3x) + 2(x + 4) = 20

Reorder the terms:
3 + 3x + 2(4 + x) = 20
3 + 3x + (4 * 2 + x * 2) = 20
3 + 3x + (8 + 2x) = 20

Reorder the terms:
3 + 8 + 3x + 2x = 20

Combine like terms: 3 + 8 = 11
11 + 3x + 2x = 20

Combine like terms: 3x + 2x = 5x
11 + 5x = 20

Solving
11 + 5x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 5x = 20 + -11

Combine like terms: 11 + -11 = 0
0 + 5x = 20 + -11
5x = 20 + -11

Combine like terms: 20 + -11 = 9
5x = 9

Divide each side by '5'.
x = 1.8

Simplifying
x = 1.8

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