3(x+1)+2(x-2)-(x-3)=30

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Solution for 3(x+1)+2(x-2)-(x-3)=30 equation: 



3(x+1)+2(x-2)-(x-3)=30

We move all terms to the left:

3(x+1)+2(x-2)-(x-3)-(30)=0

We multiply parentheses

3x+2x-(x-3)+3-4-30=0

We get rid of parentheses

3x+2x-x+3+3-4-30=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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