3(x+1)+2(x-3)=5(x+1)+8

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Solution for 3(x+1)+2(x-3)=5(x+1)+8 equation: 


Simplifying
3(x + 1) + 2(x + -3) = 5(x + 1) + 8

Reorder the terms:
3(1 + x) + 2(x + -3) = 5(x + 1) + 8
(1 * 3 + x * 3) + 2(x + -3) = 5(x + 1) + 8
(3 + 3x) + 2(x + -3) = 5(x + 1) + 8

Reorder the terms:
3 + 3x + 2(-3 + x) = 5(x + 1) + 8
3 + 3x + (-3 * 2 + x * 2) = 5(x + 1) + 8
3 + 3x + (-6 + 2x) = 5(x + 1) + 8

Reorder the terms:
3 + -6 + 3x + 2x = 5(x + 1) + 8

Combine like terms: 3 + -6 = -3
-3 + 3x + 2x = 5(x + 1) + 8

Combine like terms: 3x + 2x = 5x
-3 + 5x = 5(x + 1) + 8

Reorder the terms:
-3 + 5x = 5(1 + x) + 8
-3 + 5x = (1 * 5 + x * 5) + 8
-3 + 5x = (5 + 5x) + 8

Reorder the terms:
-3 + 5x = 5 + 8 + 5x

Combine like terms: 5 + 8 = 13
-3 + 5x = 13 + 5x

Add '-5x' to each side of the equation.
-3 + 5x + -5x = 13 + 5x + -5x

Combine like terms: 5x + -5x = 0
-3 + 0 = 13 + 5x + -5x
-3 = 13 + 5x + -5x

Combine like terms: 5x + -5x = 0
-3 = 13 + 0
-3 = 13

Solving
-3 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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