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3(x+1)+2x-18=5(x-3)
We move all terms to the left:
3(x+1)+2x-18-(5(x-3))=0
We add all the numbers together, and all the variables
2x+3(x+1)-(5(x-3))-18=0
We multiply parentheses
2x+3x-(5(x-3))+3-18=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
5x-(5x-15)-15=0
We get rid of parentheses
5x-5x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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