3(x+1)+2x=-2(x-2)+6

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Solution for 3(x+1)+2x=-2(x-2)+6 equation: 



3(x+1)+2x=-2(x-2)+6

We move all terms to the left:

3(x+1)+2x-(-2(x-2)+6)=0

We add all the numbers together, and all the variables

2x+3(x+1)-(-2(x-2)+6)=0

We multiply parentheses

2x+3x-(-2(x-2)+6)+3=0



We calculate terms in parentheses: -(-2(x-2)+6), so:

-2(x-2)+6

We multiply parentheses

-2x+4+6

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

5x-(-2x+10)+3=0

We get rid of parentheses

5x+2x-10+3=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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