3(x+1)+3(2x+5)/9=x+2

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Solution for 3(x+1)+3(2x+5)/9=x+2 equation: 



3(x+1)+3(2x+5)/9=x+2

We move all terms to the left:

3(x+1)+3(2x+5)/9-(x+2)=0

We multiply parentheses

3x+3(2x+5)/9-(x+2)+3=0

We get rid of parentheses

3x+3(2x+5)/9-x-2+3=0

We multiply all the terms by the denominator


3x*9+3(2x+5)-x*9-2*9+3*9=0

We add all the numbers together, and all the variables

3x*9+3(2x+5)-x*9+9=0

We multiply parentheses

3x*9+6x-x*9+15+9=0

Wy multiply elements

27x+6x-9x+15+9=0

We add all the numbers together, and all the variables

24x+24=0

We move all terms containing x to the left, all other terms to the right

24x=-24

x=-24/24

x=-1

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