3(x+1)+3(2x+5)=x+2

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Solution for 3(x+1)+3(2x+5)=x+2 equation: 



3(x+1)+3(2x+5)=x+2

We move all terms to the left:

3(x+1)+3(2x+5)-(x+2)=0

We multiply parentheses

3x+6x-(x+2)+3+15=0

We get rid of parentheses

3x+6x-x-2+3+15=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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