3(x+1)+3x=-3(x-1)+3

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Solution for 3(x+1)+3x=-3(x-1)+3 equation: 



3(x+1)+3x=-3(x-1)+3

We move all terms to the left:

3(x+1)+3x-(-3(x-1)+3)=0

We add all the numbers together, and all the variables

3x+3(x+1)-(-3(x-1)+3)=0

We multiply parentheses

3x+3x-(-3(x-1)+3)+3=0



We calculate terms in parentheses: -(-3(x-1)+3), so:

-3(x-1)+3

We multiply parentheses

-3x+3+3

We add all the numbers together, and all the variables

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

6x-(-3x+6)+3=0

We get rid of parentheses

6x+3x-6+3=0

We add all the numbers together, and all the variables

9x-3=0

We move all terms containing x to the left, all other terms to the right

9x=3

x=3/9

x=1/3

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