3(x+1)+4(x+2)=32

Solution for 3(x+1)+4(x+2)=32 equation:

Simplifying
3(x + 1) + 4(x + 2) = 32

Reorder the terms:
3(1 + x) + 4(x + 2) = 32
(1 * 3 + x * 3) + 4(x + 2) = 32
(3 + 3x) + 4(x + 2) = 32

Reorder the terms:
3 + 3x + 4(2 + x) = 32
3 + 3x + (2 * 4 + x * 4) = 32
3 + 3x + (8 + 4x) = 32

Reorder the terms:
3 + 8 + 3x + 4x = 32

Combine like terms: 3 + 8 = 11
11 + 3x + 4x = 32

Combine like terms: 3x + 4x = 7x
11 + 7x = 32

Solving
11 + 7x = 32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 7x = 32 + -11

Combine like terms: 11 + -11 = 0
0 + 7x = 32 + -11
7x = 32 + -11

Combine like terms: 32 + -11 = 21
7x = 21

Divide each side by '7'.
x = 3

Simplifying
x = 3