3(x+1)+4=2(x+1)+x

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Solution for 3(x+1)+4=2(x+1)+x equation: 


Simplifying
3(x + 1) + 4 = 2(x + 1) + x

Reorder the terms:
3(1 + x) + 4 = 2(x + 1) + x
(1 * 3 + x * 3) + 4 = 2(x + 1) + x
(3 + 3x) + 4 = 2(x + 1) + x

Reorder the terms:
3 + 4 + 3x = 2(x + 1) + x

Combine like terms: 3 + 4 = 7
7 + 3x = 2(x + 1) + x

Reorder the terms:
7 + 3x = 2(1 + x) + x
7 + 3x = (1 * 2 + x * 2) + x
7 + 3x = (2 + 2x) + x

Combine like terms: 2x + x = 3x
7 + 3x = 2 + 3x

Add '-3x' to each side of the equation.
7 + 3x + -3x = 2 + 3x + -3x

Combine like terms: 3x + -3x = 0
7 + 0 = 2 + 3x + -3x
7 = 2 + 3x + -3x

Combine like terms: 3x + -3x = 0
7 = 2 + 0
7 = 2

Solving
7 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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