3(x+1)+4x=-4(x-3)-4

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Solution for 3(x+1)+4x=-4(x-3)-4 equation:



3(x+1)+4x=-4(x-3)-4
We move all terms to the left:
3(x+1)+4x-(-4(x-3)-4)=0
We add all the numbers together, and all the variables
4x+3(x+1)-(-4(x-3)-4)=0
We multiply parentheses
4x+3x-(-4(x-3)-4)+3=0
We calculate terms in parentheses: -(-4(x-3)-4), so:
-4(x-3)-4
We multiply parentheses
-4x+12-4
We add all the numbers together, and all the variables
-4x+8
Back to the equation:
-(-4x+8)
We add all the numbers together, and all the variables
7x-(-4x+8)+3=0
We get rid of parentheses
7x+4x-8+3=0
We add all the numbers together, and all the variables
11x-5=0
We move all terms containing x to the left, all other terms to the right
11x=5
x=5/11
x=5/11

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