3(x+1)+5=2(3x-1)-8

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Solution for 3(x+1)+5=2(3x-1)-8 equation: 



3(x+1)+5=2(3x-1)-8

We move all terms to the left:

3(x+1)+5-(2(3x-1)-8)=0

We multiply parentheses

3x-(2(3x-1)-8)+3+5=0



We calculate terms in parentheses: -(2(3x-1)-8), so:

2(3x-1)-8

We multiply parentheses

6x-2-8

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We add all the numbers together, and all the variables

3x-(6x-10)+8=0

We get rid of parentheses

3x-6x+10+8=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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