3(x+1)+6=3(x+1)+x-(x+2)

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Solution for 3(x+1)+6=3(x+1)+x-(x+2) equation: 



3(x+1)+6=3(x+1)+x-(x+2)

We move all terms to the left:

3(x+1)+6-(3(x+1)+x-(x+2))=0

We multiply parentheses

3x-(3(x+1)+x-(x+2))+3+6=0



We calculate terms in parentheses: -(3(x+1)+x-(x+2)), so:

3(x+1)+x-(x+2)

We add all the numbers together, and all the variables

x+3(x+1)-(x+2)

We multiply parentheses

x+3x-(x+2)+3

We get rid of parentheses

x+3x-x-2+3

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

3x-(3x+1)+9=0

We get rid of parentheses

3x-3x-1+9=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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