3(x+1)+7(x+3)=64

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Solution for 3(x+1)+7(x+3)=64 equation:


Simplifying
3(x + 1) + 7(x + 3) = 64

Reorder the terms:
3(1 + x) + 7(x + 3) = 64
(1 * 3 + x * 3) + 7(x + 3) = 64
(3 + 3x) + 7(x + 3) = 64

Reorder the terms:
3 + 3x + 7(3 + x) = 64
3 + 3x + (3 * 7 + x * 7) = 64
3 + 3x + (21 + 7x) = 64

Reorder the terms:
3 + 21 + 3x + 7x = 64

Combine like terms: 3 + 21 = 24
24 + 3x + 7x = 64

Combine like terms: 3x + 7x = 10x
24 + 10x = 64

Solving
24 + 10x = 64

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + -24 + 10x = 64 + -24

Combine like terms: 24 + -24 = 0
0 + 10x = 64 + -24
10x = 64 + -24

Combine like terms: 64 + -24 = 40
10x = 40

Divide each side by '10'.
x = 4

Simplifying
x = 4

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