3(x+1)+7(x=3)=64

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Solution for 3(x+1)+7(x=3)=64 equation: 



3(x+1)+7(x=3)=64

We move all terms to the left:

3(x+1)+7(x-(3))=0

We multiply parentheses

3x+7x+3-21=0

We add all the numbers together, and all the variables

10x-18=0

We move all terms containing x to the left, all other terms to the right

10x=18

x=18/10

x=1+4/5

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