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3(x+1)+7=4x-3(2-x)
We move all terms to the left:
3(x+1)+7-(4x-3(2-x))=0
We add all the numbers together, and all the variables
3(x+1)-(4x-3(-1x+2))+7=0
We multiply parentheses
3x-(4x-3(-1x+2))+3+7=0
We calculate terms in parentheses: -(4x-3(-1x+2)), so:We add all the numbers together, and all the variables
4x-3(-1x+2)
We multiply parentheses
4x+3x-6
We add all the numbers together, and all the variables
7x-6
Back to the equation:
-(7x-6)
3x-(7x-6)+10=0
We get rid of parentheses
3x-7x+6+10=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4
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