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3(x+1)+9=2(x+6)+6
We move all terms to the left:
3(x+1)+9-(2(x+6)+6)=0
We multiply parentheses
3x-(2(x+6)+6)+3+9=0
We calculate terms in parentheses: -(2(x+6)+6), so:We add all the numbers together, and all the variables
2(x+6)+6
We multiply parentheses
2x+12+6
We add all the numbers together, and all the variables
2x+18
Back to the equation:
-(2x+18)
3x-(2x+18)+12=0
We get rid of parentheses
3x-2x-18+12=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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