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3(x+1)+x=2(x-1)+x
We move all terms to the left:
3(x+1)+x-(2(x-1)+x)=0
We add all the numbers together, and all the variables
x+3(x+1)-(2(x-1)+x)=0
We multiply parentheses
x+3x-(2(x-1)+x)+3=0
We calculate terms in parentheses: -(2(x-1)+x), so:We add all the numbers together, and all the variables
2(x-1)+x
We add all the numbers together, and all the variables
x+2(x-1)
We multiply parentheses
x+2x-2
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
4x-(3x-2)+3=0
We get rid of parentheses
4x-3x+2+3=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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