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3(x+1)-(x-1)*2=10-(5+3x)
We move all terms to the left:
3(x+1)-(x-1)*2-(10-(5+3x))=0
We add all the numbers together, and all the variables
3(x+1)-(x-1)*2-(10-(3x+5))=0
We multiply parentheses
3x-2x-(10-(3x+5))+3+2=0
We calculate terms in parentheses: -(10-(3x+5)), so:We add all the numbers together, and all the variables
10-(3x+5)
determiningTheFunctionDomain -(3x+5)+10
We get rid of parentheses
-3x-5+10
We add all the numbers together, and all the variables
-3x+5
Back to the equation:
-(-3x+5)
x-(-3x+5)+5=0
We get rid of parentheses
x+3x-5+5=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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