3(x+1)-(x-2)=2(x+4)

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Solution for 3(x+1)-(x-2)=2(x+4) equation:


Simplifying
3(x + 1) + -1(x + -2) = 2(x + 4)

Reorder the terms:
3(1 + x) + -1(x + -2) = 2(x + 4)
(1 * 3 + x * 3) + -1(x + -2) = 2(x + 4)
(3 + 3x) + -1(x + -2) = 2(x + 4)

Reorder the terms:
3 + 3x + -1(-2 + x) = 2(x + 4)
3 + 3x + (-2 * -1 + x * -1) = 2(x + 4)
3 + 3x + (2 + -1x) = 2(x + 4)

Reorder the terms:
3 + 2 + 3x + -1x = 2(x + 4)

Combine like terms: 3 + 2 = 5
5 + 3x + -1x = 2(x + 4)

Combine like terms: 3x + -1x = 2x
5 + 2x = 2(x + 4)

Reorder the terms:
5 + 2x = 2(4 + x)
5 + 2x = (4 * 2 + x * 2)
5 + 2x = (8 + 2x)

Add '-2x' to each side of the equation.
5 + 2x + -2x = 8 + 2x + -2x

Combine like terms: 2x + -2x = 0
5 + 0 = 8 + 2x + -2x
5 = 8 + 2x + -2x

Combine like terms: 2x + -2x = 0
5 = 8 + 0
5 = 8

Solving
5 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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