3(x+1)-(x-4)=17

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Solution for 3(x+1)-(x-4)=17 equation: 



3(x+1)-(x-4)=17

We move all terms to the left:

3(x+1)-(x-4)-(17)=0

We multiply parentheses

3x-(x-4)+3-17=0

We get rid of parentheses

3x-x+4+3-17=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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