3(x+1)-(x-9)+(x-9)+(x+3)=(x+4)+(x+2)-(11-x)

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Solution for 3(x+1)-(x-9)+(x-9)+(x+3)=(x+4)+(x+2)-(11-x) equation: 



3(x+1)-(x-9)+(x-9)+(x+3)=(x+4)+(x+2)-(11-x)

We move all terms to the left:

3(x+1)-(x-9)+(x-9)+(x+3)-((x+4)+(x+2)-(11-x))=0

We add all the numbers together, and all the variables

3(x+1)-(x-9)+(x-9)+(x+3)-((x+4)+(x+2)-(-1x+11))=0

We multiply parentheses

3x-(x-9)+(x-9)+(x+3)-((x+4)+(x+2)-(-1x+11))+3=0

We get rid of parentheses

3x-x+x+x-((x+4)+(x+2)-(-1x+11))+9-9+3+3=0



We calculate terms in parentheses: -((x+4)+(x+2)-(-1x+11)), so:

(x+4)+(x+2)-(-1x+11)

We get rid of parentheses

x+x+1x+4+2-11

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

4x-(3x-5)+6=0

We get rid of parentheses

4x-3x+5+6=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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