3(x+1)-10=(2x+8)+x+5

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Solution for 3(x+1)-10=(2x+8)+x+5 equation:


Simplifying
3(x + 1) + -10 = (2x + 8) + x + 5

Reorder the terms:
3(1 + x) + -10 = (2x + 8) + x + 5
(1 * 3 + x * 3) + -10 = (2x + 8) + x + 5
(3 + 3x) + -10 = (2x + 8) + x + 5

Reorder the terms:
3 + -10 + 3x = (2x + 8) + x + 5

Combine like terms: 3 + -10 = -7
-7 + 3x = (2x + 8) + x + 5

Reorder the terms:
-7 + 3x = (8 + 2x) + x + 5

Remove parenthesis around (8 + 2x)
-7 + 3x = 8 + 2x + x + 5

Reorder the terms:
-7 + 3x = 8 + 5 + 2x + x

Combine like terms: 8 + 5 = 13
-7 + 3x = 13 + 2x + x

Combine like terms: 2x + x = 3x
-7 + 3x = 13 + 3x

Add '-3x' to each side of the equation.
-7 + 3x + -3x = 13 + 3x + -3x

Combine like terms: 3x + -3x = 0
-7 + 0 = 13 + 3x + -3x
-7 = 13 + 3x + -3x

Combine like terms: 3x + -3x = 0
-7 = 13 + 0
-7 = 13

Solving
-7 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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