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3(x+1)-2(2x-5)=6x-3
We move all terms to the left:
3(x+1)-2(2x-5)-(6x-3)=0
We multiply parentheses
3x-4x-(6x-3)+3+10=0
We get rid of parentheses
3x-4x-6x+3+3+10=0
We add all the numbers together, and all the variables
-7x+16=0
We move all terms containing x to the left, all other terms to the right
-7x=-16
x=-16/-7
x=2+2/7
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