3(x+1)-2(x-4)=13

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Solution for 3(x+1)-2(x-4)=13 equation: 


Simplifying
3(x + 1) + -2(x + -4) = 13

Reorder the terms:
3(1 + x) + -2(x + -4) = 13
(1 * 3 + x * 3) + -2(x + -4) = 13
(3 + 3x) + -2(x + -4) = 13

Reorder the terms:
3 + 3x + -2(-4 + x) = 13
3 + 3x + (-4 * -2 + x * -2) = 13
3 + 3x + (8 + -2x) = 13

Reorder the terms:
3 + 8 + 3x + -2x = 13

Combine like terms: 3 + 8 = 11
11 + 3x + -2x = 13

Combine like terms: 3x + -2x = 1x
11 + 1x = 13

Solving
11 + 1x = 13

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 1x = 13 + -11

Combine like terms: 11 + -11 = 0
0 + 1x = 13 + -11
1x = 13 + -11

Combine like terms: 13 + -11 = 2
1x = 2

Divide each side by '1'.
x = 2

Simplifying
x = 2

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