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3(x+1)-2=6x-3(1+x)
We move all terms to the left:
3(x+1)-2-(6x-3(1+x))=0
We add all the numbers together, and all the variables
3(x+1)-(6x-3(x+1))-2=0
We multiply parentheses
3x-(6x-3(x+1))+3-2=0
We calculate terms in parentheses: -(6x-3(x+1)), so:We add all the numbers together, and all the variables
6x-3(x+1)
We multiply parentheses
6x-3x-3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
3x-(3x-3)+1=0
We get rid of parentheses
3x-3x+3+1=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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