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3(x+1)-3=4(x-5)
We move all terms to the left:
3(x+1)-3-(4(x-5))=0
We multiply parentheses
3x-(4(x-5))+3-3=0
We calculate terms in parentheses: -(4(x-5)), so:We add all the numbers together, and all the variables
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
3x-(4x-20)=0
We get rid of parentheses
3x-4x+20=0
We add all the numbers together, and all the variables
-1x+20=0
We move all terms containing x to the left, all other terms to the right
-x=-20
x=-20/-1
x=+20
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