3(x+1)-4(y-1)=13

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Solution for 3(x+1)-4(y-1)=13 equation:


Simplifying
3(x + 1) + -4(y + -1) = 13

Reorder the terms:
3(1 + x) + -4(y + -1) = 13
(1 * 3 + x * 3) + -4(y + -1) = 13
(3 + 3x) + -4(y + -1) = 13

Reorder the terms:
3 + 3x + -4(-1 + y) = 13
3 + 3x + (-1 * -4 + y * -4) = 13
3 + 3x + (4 + -4y) = 13

Reorder the terms:
3 + 4 + 3x + -4y = 13

Combine like terms: 3 + 4 = 7
7 + 3x + -4y = 13

Solving
7 + 3x + -4y = 13

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + 3x + -7 + -4y = 13 + -7

Reorder the terms:
7 + -7 + 3x + -4y = 13 + -7

Combine like terms: 7 + -7 = 0
0 + 3x + -4y = 13 + -7
3x + -4y = 13 + -7

Combine like terms: 13 + -7 = 6
3x + -4y = 6

Add '4y' to each side of the equation.
3x + -4y + 4y = 6 + 4y

Combine like terms: -4y + 4y = 0
3x + 0 = 6 + 4y
3x = 6 + 4y

Divide each side by '3'.
x = 2 + 1.333333333y

Simplifying
x = 2 + 1.333333333y

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