3(x+1)-5(x+10)=9(x-4)-9(x-8)

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Solution for 3(x+1)-5(x+10)=9(x-4)-9(x-8) equation: 



3(x+1)-5(x+10)=9(x-4)-9(x-8)

We move all terms to the left:

3(x+1)-5(x+10)-(9(x-4)-9(x-8))=0

We multiply parentheses

3x-5x-(9(x-4)-9(x-8))+3-50=0



We calculate terms in parentheses: -(9(x-4)-9(x-8)), so:

9(x-4)-9(x-8)

We multiply parentheses

9x-9x-36+72

We add all the numbers together, and all the variables

36

Back to the equation:

-(36)



We add all the numbers together, and all the variables

-2x-83=0

We move all terms containing x to the left, all other terms to the right

-2x=83

x=83/-2

x=-41+1/2

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