3(x+1)-5(x+5)=4(1-2x)-2(x-3)

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Solution for 3(x+1)-5(x+5)=4(1-2x)-2(x-3) equation: 



3(x+1)-5(x+5)=4(1-2x)-2(x-3)

We move all terms to the left:

3(x+1)-5(x+5)-(4(1-2x)-2(x-3))=0

We add all the numbers together, and all the variables

3(x+1)-5(x+5)-(4(-2x+1)-2(x-3))=0

We multiply parentheses

3x-5x-(4(-2x+1)-2(x-3))+3-25=0



We calculate terms in parentheses: -(4(-2x+1)-2(x-3)), so:

4(-2x+1)-2(x-3)

We multiply parentheses

-8x-2x+4+6

We add all the numbers together, and all the variables

-10x+10

Back to the equation:

-(-10x+10)



We add all the numbers together, and all the variables

-2x-(-10x+10)-22=0

We get rid of parentheses

-2x+10x-10-22=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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