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3(x+1)-5=(5x-2)
We move all terms to the left:
3(x+1)-5-((5x-2))=0
We multiply parentheses
3x-((5x-2))+3-5=0
We calculate terms in parentheses: -((5x-2)), so:We add all the numbers together, and all the variables
(5x-2)
We get rid of parentheses
5x-2
Back to the equation:
-(5x-2)
3x-(5x-2)-2=0
We get rid of parentheses
3x-5x+2-2=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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