3(x+1)-5=2(x-3)+1

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Solution for 3(x+1)-5=2(x-3)+1 equation: 



3(x+1)-5=2(x-3)+1

We move all terms to the left:

3(x+1)-5-(2(x-3)+1)=0

We multiply parentheses

3x-(2(x-3)+1)+3-5=0



We calculate terms in parentheses: -(2(x-3)+1), so:

2(x-3)+1

We multiply parentheses

2x-6+1

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

3x-(2x-5)-2=0

We get rid of parentheses

3x-2x+5-2=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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