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3(x+1)-5=2x-5(x+8)
We move all terms to the left:
3(x+1)-5-(2x-5(x+8))=0
We multiply parentheses
3x-(2x-5(x+8))+3-5=0
We calculate terms in parentheses: -(2x-5(x+8)), so:We add all the numbers together, and all the variables
2x-5(x+8)
We multiply parentheses
2x-5x-40
We add all the numbers together, and all the variables
-3x-40
Back to the equation:
-(-3x-40)
3x-(-3x-40)-2=0
We get rid of parentheses
3x+3x+40-2=0
We add all the numbers together, and all the variables
6x+38=0
We move all terms containing x to the left, all other terms to the right
6x=-38
x=-38/6
x=-6+1/3
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