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3(x+1)-6=2(2x+1)
We move all terms to the left:
3(x+1)-6-(2(2x+1))=0
We multiply parentheses
3x-(2(2x+1))+3-6=0
We calculate terms in parentheses: -(2(2x+1)), so:We add all the numbers together, and all the variables
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
-(4x+2)
3x-(4x+2)-3=0
We get rid of parentheses
3x-4x-2-3=0
We add all the numbers together, and all the variables
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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