3(x+1)-7=5x-2(2+x)

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Solution for 3(x+1)-7=5x-2(2+x) equation: 



3(x+1)-7=5x-2(2+x)

We move all terms to the left:

3(x+1)-7-(5x-2(2+x))=0

We add all the numbers together, and all the variables

3(x+1)-(5x-2(x+2))-7=0

We multiply parentheses

3x-(5x-2(x+2))+3-7=0



We calculate terms in parentheses: -(5x-2(x+2)), so:

5x-2(x+2)

We multiply parentheses

5x-2x-4

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

3x-(3x-4)-4=0

We get rid of parentheses

3x-3x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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