3(x+1)-8=4(1+x)+5

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Solution for 3(x+1)-8=4(1+x)+5 equation: 


Simplifying
3(x + 1) + -8 = 4(1 + x) + 5

Reorder the terms:
3(1 + x) + -8 = 4(1 + x) + 5
(1 * 3 + x * 3) + -8 = 4(1 + x) + 5
(3 + 3x) + -8 = 4(1 + x) + 5

Reorder the terms:
3 + -8 + 3x = 4(1 + x) + 5

Combine like terms: 3 + -8 = -5
-5 + 3x = 4(1 + x) + 5
-5 + 3x = (1 * 4 + x * 4) + 5
-5 + 3x = (4 + 4x) + 5

Reorder the terms:
-5 + 3x = 4 + 5 + 4x

Combine like terms: 4 + 5 = 9
-5 + 3x = 9 + 4x

Solving
-5 + 3x = 9 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-5 + 3x + -4x = 9 + 4x + -4x

Combine like terms: 3x + -4x = -1x
-5 + -1x = 9 + 4x + -4x

Combine like terms: 4x + -4x = 0
-5 + -1x = 9 + 0
-5 + -1x = 9

Add '5' to each side of the equation.
-5 + 5 + -1x = 9 + 5

Combine like terms: -5 + 5 = 0
0 + -1x = 9 + 5
-1x = 9 + 5

Combine like terms: 9 + 5 = 14
-1x = 14

Divide each side by '-1'.
x = -14

Simplifying
x = -14

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