3(x+1)-8=4(1+x)=5

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Solution for 3(x+1)-8=4(1+x)=5 equation:



3(x+1)-8=4(1+x)=5
We move all terms to the left:
3(x+1)-8-(4(1+x))=0
We add all the numbers together, and all the variables
3(x+1)-(4(x+1))-8=0
We multiply parentheses
3x-(4(x+1))+3-8=0
We calculate terms in parentheses: -(4(x+1)), so:
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
We add all the numbers together, and all the variables
3x-(4x+4)-5=0
We get rid of parentheses
3x-4x-4-5=0
We add all the numbers together, and all the variables
-1x-9=0
We move all terms containing x to the left, all other terms to the right
-x=9
x=9/-1
x=-9

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