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3(x+1)-x=2(x+3)
We move all terms to the left:
3(x+1)-x-(2(x+3))=0
We add all the numbers together, and all the variables
-1x+3(x+1)-(2(x+3))=0
We multiply parentheses
-1x+3x-(2(x+3))+3=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
2x-(2x+6)+3=0
We get rid of parentheses
2x-2x-6+3=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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