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3(x+1)/4=x+2
We move all terms to the left:
3(x+1)/4-(x+2)=0
We get rid of parentheses
3(x+1)/4-x-2=0
We multiply all the terms by the denominator
3(x+1)-x*4-2*4=0
We add all the numbers together, and all the variables
3(x+1)-x*4-8=0
We multiply parentheses
3x-x*4+3-8=0
Wy multiply elements
3x-4x+3-8=0
We add all the numbers together, and all the variables
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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