3(x+1)/5=2(3x-4)/6+2

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Solution for 3(x+1)/5=2(3x-4)/6+2 equation: 



3(x+1)/5=2(3x-4)/6+2

We move all terms to the left:

3(x+1)/5-(2(3x-4)/6+2)=0

We calculate fractions


(18x+18)/()+(-(2(3x-4)*5)/()=0



We calculate terms in parentheses: +(-(2(3x-4)*5)/(), so:

-(2(3x-4)*5)/(

We multiply all the terms by the denominator


-(2(3x-4)*5)



We calculate terms in parentheses: -(2(3x-4)*5), so:

2(3x-4)*5

We multiply parentheses

30x-40

Back to the equation:

-(30x-40)



We get rid of parentheses

-30x+40

Back to the equation:

+(-30x+40)



We get rid of parentheses

(18x+18)/()-30x+40=0

We multiply all the terms by the denominator


(18x+18)-30x*()+40*()=0

We add all the numbers together, and all the variables

(18x+18)-30x*()=0

We get rid of parentheses

18x-30x*()+18=0

We move all terms containing x to the left, all other terms to the right

18x-30x*()=-18

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