3(x+1)/8=2x-4

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Solution for 3(x+1)/8=2x-4 equation: 



3(x+1)/8=2x-4

We move all terms to the left:

3(x+1)/8-(2x-4)=0

We get rid of parentheses

3(x+1)/8-2x+4=0

We multiply all the terms by the denominator


3(x+1)-2x*8+4*8=0

We add all the numbers together, and all the variables

3(x+1)-2x*8+32=0

We multiply parentheses

3x-2x*8+3+32=0

Wy multiply elements

3x-16x+3+32=0

We add all the numbers together, and all the variables

-13x+35=0

We move all terms containing x to the left, all other terms to the right

-13x=-35

x=-35/-13

x=2+9/13

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